The equation y = -16t^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball reach 110 feet? Express your answer as a decimal rounded to the nearest tenth.

Guest Jul 11, 2021

#1**0 **

110 = - 16t^2 + 26t + 105

-16t^2 +26t -5 = 0 Use Quadratic fromula with a = -16 b = 26 c = -5 to solve for two values of t the lower one will be for the

ball on the way up..... the larger represents the time when the ball is on the way down.

ElectricPavlov Jul 11, 2021